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sed: fix commandline-given expression when -e is not used
Make explicit sed commands (first on commandline) behave the same as those given with -e. Without this patch the following two commands behave differently, the second one being wrong: echo ab | sed -e $'1 i\\\n--' echo ab | sed $'1 i\\\n--' Reviewed by: 0mp, des, kevans Sponsored by: Klara, Inc. Differential Revision: https://reviews.freebsd.org/D47377
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@ -137,10 +137,8 @@ main(int argc, char *argv[])
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break;
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case 'e':
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eflag = 1;
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if ((temp_arg = malloc(strlen(optarg) + 2)) == NULL)
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err(1, "malloc");
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strcpy(temp_arg, optarg);
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strcat(temp_arg, "\n");
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if (asprintf(&temp_arg, "%s\n", optarg) == -1)
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err(1, "asprintf");
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add_compunit(CU_STRING, temp_arg);
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break;
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case 'f':
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@ -173,7 +171,9 @@ main(int argc, char *argv[])
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/* First usage case; script is the first arg */
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if (!eflag && !fflag && *argv) {
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add_compunit(CU_STRING, *argv);
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if (asprintf(&temp_arg, "%s\n", *argv) == -1)
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err(1, "asprintf");
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add_compunit(CU_STRING, temp_arg);
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argv++;
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}
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@ -147,6 +147,18 @@ bracket_y_body()
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echo 'bra[ke]' | sed 'y[\[][ct['
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}
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atf_test_case minus_e
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minus_e_head()
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{
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atf_set "descr" "Verify that -e and implicit arg do the same thing"
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}
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minus_e_body()
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{
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printf "ab\n" > a
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atf_check -o 'inline:--\nab\n' sed -e $'1 i\\\n--' a
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atf_check -o 'inline:--\nab\n' sed $'1 i\\\n--' a
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}
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atf_init_test_cases()
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{
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atf_add_test_case inplace_command_q
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@ -156,4 +168,5 @@ atf_init_test_cases()
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atf_add_test_case commands_on_stdin
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atf_add_test_case hex_subst
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atf_add_test_case bracket_y
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atf_add_test_case minus_e
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}
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