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3a17de1501
- If the user doesn't have an OPIE key, don't challenge him. This is a workaround until I get PAM to work properly with ssh2. Sponsored by: DARPA, NAI Labs
100 lines
2.7 KiB
C
100 lines
2.7 KiB
C
/*
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* Copyright (c) 2001 Markus Friedl. All rights reserved.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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*
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* THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
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* IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
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* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
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* IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
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* INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
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* NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
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* DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
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* THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
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* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
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* THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
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*/
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#include "includes.h"
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RCSID("$OpenBSD: auth-skey.c,v 1.16 2002/01/12 13:10:29 markus Exp $");
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RCSID("$FreeBSD$");
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#ifdef SKEY
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#include <opie.h>
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#include "xmalloc.h"
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#include "auth.h"
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static void *
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skey_init_ctx(Authctxt *authctxt)
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{
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return authctxt;
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}
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#define PROMPT "\nOPIE Password: "
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static int
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skey_query(void *ctx, char **name, char **infotxt,
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u_int* numprompts, char ***prompts, u_int **echo_on)
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{
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Authctxt *authctxt = ctx;
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char challenge[1024], *p;
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int len;
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struct opie opie;
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if (opie_haskey(authctxt->user) != 0)
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return -1;
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if (opiechallenge(&opie, authctxt->user, challenge) == -1)
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return -1;
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*name = xstrdup("");
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*infotxt = xstrdup("");
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*numprompts = 1;
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*prompts = xmalloc(*numprompts * sizeof(char*));
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*echo_on = xmalloc(*numprompts * sizeof(u_int));
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(*echo_on)[0] = 0;
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len = strlen(challenge) + strlen(PROMPT) + 1;
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p = xmalloc(len);
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strlcpy(p, challenge, len);
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strlcat(p, PROMPT, len);
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(*prompts)[0] = p;
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return 0;
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}
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static int
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skey_respond(void *ctx, u_int numresponses, char **responses)
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{
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Authctxt *authctxt = ctx;
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if (authctxt->valid &&
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numresponses == 1 &&
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opie_haskey(authctxt->pw->pw_name) == 0 &&
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opie_passverify(authctxt->pw->pw_name, responses[0]) != -1)
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return 0;
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return -1;
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}
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static void
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skey_free_ctx(void *ctx)
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{
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/* we don't have a special context */
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}
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KbdintDevice skey_device = {
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"skey",
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skey_init_ctx,
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skey_query,
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skey_respond,
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skey_free_ctx
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};
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#endif /* SKEY */
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